8x^2=28x+60

Solution for 8x^2=28x+60 equation:

8x^2=28x+60

We move all terms to the left:

8x^2-(28x+60)=0

We get rid of parentheses

8x^2-28x-60=0

a = 8; b = -28; c = -60;
Δ = b2-4ac
Δ = -282-4·8·(-60)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-52}{2*8}=\frac{-24}{16}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+52}{2*8}=\frac{80}{16}
=5
$